Join the IDNLearn.com community and get your questions answered by experts. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.
The moles of Na⁺ in 1.30 L is 0.2158 moles of Na⁺.
Concentration of a solution is the amount of solute present in a given volume of solution or solvent.
The concentration of the Na⁺ in the intravenous saline solution contains 166 mEq/L.
1 mEq/Liter = 1 mmol/L
Moles of Na⁺ in 1.30 L = M
[tex]M = {166 mEq/L} * \frac{1 mmol/L}{1 mEq/L} * \frac{1.30 L}{1000 mL} = 0.2158\:moles[/tex]
Moles of Na⁺ in 1.30 L = 0.2158 moles of Na⁺.
Learn more about concentration at: https://brainly.com/question/24595796
#SPJ1