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The moles of Na⁺ in 1.30 L is 0.2158 moles of Na⁺.
Concentration of a solution is the amount of solute present in a given volume of solution or solvent.
The concentration of the Na⁺ in the intravenous saline solution contains 166 mEq/L.
1 mEq/Liter = 1 mmol/L
Moles of Na⁺ in 1.30 L = M
[tex]M = {166 mEq/L} * \frac{1 mmol/L}{1 mEq/L} * \frac{1.30 L}{1000 mL} = 0.2158\:moles[/tex]
Moles of Na⁺ in 1.30 L = 0.2158 moles of Na⁺.
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