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A +0.05 C charge is placed in a uniform electric field pointing downward with a strength of 100 Newtons over Coulombs.. Determine the magnitude and direction of the force on the charge.

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The magnitude of the electric force on the charge is 5 N.

Magnitude of force on the charge

The magnitude of force on the charge is calculated as follows;

F = Eq

where;

  • E is electric field
  • q is magnitude of the charge

F = 100 N/C  x 0.05 C

F = 5 N

Thus, the magnitude of the electric force on the charge is 5 N.

Learn more about electric force here: https://brainly.com/question/20880591

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