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8. A 15.0 gram unknown piece of metal at 99 oC is added to 75 grams of water at 23 oC. The final temperature of the metal and water is 26 oC. What is the specific heat of the unknown metal? (Remember that the specific heat of water is 4.18 J/g* oC.)

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The specific heat of the unknown metal is 0.859 J/g⁰C.

Specific heat of the unknown metal

Heat lost by the unknown metal = Heat gained by water

m₁c₁Δθ₁ = m₂c₂Δθ₂

where;

  • c₁ is specific heat of the unknown metal
  • c₂ is specific heat of water

(15)(c₁)(99 - 26) = (75)(4.18)(26 - 23)

1095c₁ = 940.5

c₁ = 940.5/1095

c₁ = 0.859 J/g⁰C

Learn more about specific heat here: https://brainly.com/question/16559442

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