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Could you help me with this geometry question?

Could You Help Me With This Geometry Question class=

Sagot :

Ogorwyneidn

The value of <RQZ has been calculated as 21 from the solution we have below.

How to solve for RQZ

We have

< PZQ= <PQZ

PQR - PRQ = 42

Let < PZQ = y⁰

PQZ = y⁰

Let PRQ = x⁰

< PQR = x + 42⁰

< QpZ + y + y = 180⁰

such that

QPZ + 2y = 180⁰

<QPZ = 180⁰ - 2y

<(QPZ + PQR + PRQ) = 180

Adding these equations, we would have

180 - 2y + x + 42 + x = 180⁰

180 would cancel out

We have

2x - 2y + 42 = 0

x- y +21 = 0

We have to add 21 to both sides of the equation

x- y + 42 = 21

(x + 42) - y = 21

(x + 42) = <PQR and y = < PQZ

Hence 21 = <RQZ

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