Karinarinaidn
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Fieryanswererftidn

Answer:

[tex]\sf C. - \dfrac{3}{4}[/tex]

Explanation:

[tex]\sf Given \ equation : 4x - 3y = 12[/tex]

Rewrite in slope intercept form "y = mx + b"

[tex]\rightarrow \sf 4x - 3y = 12[/tex]

[tex]\rightarrow \sf - 3y = 12 - 4x[/tex]

[tex]\rightarrow \sf y =\dfrac{ 12 - 4x}{-3}[/tex]

[tex]\rightarrow \sf y =\dfrac{ 4}{3}x - 4[/tex]

Here the slope is 4/3 and y-intercept is -4

Perpendicular lines has negatively inverse slope.

→ per. slope = -(slope)⁻¹ = -(4/3)⁻¹ = -3/4

Semsee45idn

Answer:

[tex]-\dfrac{3}{4}[/tex]

Step-by-step explanation:

Slope-intercept form of a linear equation:

 [tex]y=mx+b[/tex]

where:

  • m is the slope
  • b is the y-intercept

Given linear equation:

  [tex]4x-3y=12[/tex]

Find the slope of the given linear equation by rewriting the equation so that it is in slope-intercept form (i.e. make y the subject):

[tex]\implies 4x-3y=12[/tex]

[tex]\implies 4x-3y+3y=12+3y[/tex]

[tex]\implies 4x=12+3y[/tex]

[tex]\implies 4x-12=12+3y-12[/tex]

[tex]\implies 4x-12=3y[/tex]

[tex]\implies \dfrac{3y}{3}=\dfrac{4}{3}x-\dfrac{12}{3}[/tex]

[tex]\implies y=\dfrac{4}{3}x-4[/tex]

Therefore, the slope of the given line is 4/3.

If two lines are perpendicular to each other, the product of their slopes will be -1.   Therefore, the slope (m) of the line perpendicular to the given line is:

[tex]\implies m \times \dfrac{4}{3}=-1[/tex]

[tex]\implies m=-\dfrac{3}{4}[/tex]

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