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A formula for the normal systolic blood pressure for a man age A , measured in mmHg, is given as P=0.006A2−0.02A+120 . Find the age of a man whose normal blood pressure measures 128 mmHg.

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The age of the man whose normal pressure measures 128 mmHg is approximately 38 years.

How do we determine the age of the man using a quadratic equation?

The quadratic formula can be used to determine the age of a man whose normal blood pressure measures 128 mmHg. This can be expressed mathematically as:

[tex]\mathbf{ \dfrac{-b \pm\sqrt{b^2 - 4ac}}{2a}}[/tex]

From the given equation:

P = 0.006A² - 0.02A + 120

where;

  • P = 128

128 =  0.006A² - 0.02A + 120

= 0.006A² - 0.02A + 120 - 128

= 0.006A² - 0.02A - 8

where:

  • a = 0.006 , b = - 0.02, and c = -8

[tex]\mathbf{ \dfrac{-(-0.02) \pm\sqrt{(-0.02)^2 - 4(0.006)(-8)}}{2(0.006)}}[/tex]

[tex]\mathbf{ = \dfrac{(0.02) \pm 0.43863}{0.012}}[/tex]

= 38.2195 or -34.8862

Taking the positive integer value, the age of the man whose normal pressure measures 128 mmHg is approximately 38 years.

Learn more about using the quadratic formulas to solve quadratic equations here:

https://brainly.com/question/8649555

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