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A rectangle has perimeter 92 cm and its length is 1 cm more than twice its width.
Find the dimensions of a rectangle given that its perimeter is 92 cm and its length is 1 cm more than twice its width.
Set up your solution using the variables L for the length, W for the width, and P for the perimeter.
Part a: Using the definition of perimeter, write an equation for P in terms of L and W .
Part b: Using the relationship given in the problem statement, write an equation for L in terms of W .
Solve the equations from parts a and b.
Part c: The width is
Number
cm.
Part d: The length is
Number
cm.

Sagot :

Abidemiokinidn

The length and width of the rectangle is 15cm and 31cm respectively

Perimeter of a rectangle

The formula for calculating the perimeter of a rectangle is expressed as:

P = 2(L + W)

where

L is the length

W is the width

If its length is 1 cm more than twice its width, then;

L = 2W + 1

Substitute

92 = 2(2W + 1 + W)

46 = 3W + 1

3W = 45

W = 15cm

Determine the length

L = 2(15) + 1

L = 31cm

Hence the length and width of the rectangle is 15cm and 31cm respectively

Learn more on perimeter of rectangle here: https://brainly.com/question/19819849

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