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Find the zeros of the function f(x)=x^2+9.9x+18. Round values to the nearest hundredth (if necessary).

Sagot :

A quadratic equation in the form of ax²+bx+c. The zeroes of the polynomial are -2.4 and -7.5.

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c. The Root of the quadratic equation are given as,

[tex]x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

The zeroes of the polynomial are:

f(x)=x² + 9.9x + 18

0 = x² + 9.9x + 18

[tex]x= \dfrac{-9.9\pm \sqrt{(9.9)^2-4(1)(18)}}{2(1)}\\\\[/tex]

x = -2.4, -7.5

Hence, the zeroes of the polynomial are -2.4 and -7.5.

Learn more about Quadratic Equations:

https://brainly.com/question/2263981

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