Connect with knowledgeable individuals and find the best answers at IDNLearn.com. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.
The mass of block 1 is 1.30176 kg.
A tension force in physics is a force developed in a rope, string, or cable when stretched under an applied force.
Tension is acted along the length of the rope/cable in a direction that is opposite to the force applied on it.
According to the question,
Mass of block 2= 11.3 kg
Kinetic friction μ=0.200
The component of the weight in the direction of the incline
W = m₂gsinθ
T = [tex]F_{f} - W[/tex]........(1)
When the force of friction
[tex]F_{f}[/tex] = μ[tex]_k[/tex]N
[tex]F_{f}[/tex] = μ[tex]_k[/tex](m₂gcosθ)
Here , Put the value in equation 1
T = m₂gcos 31.5° - μ[tex]_k[/tex]m₂gcos 31.5°
We know that ,
T - m₁g = 0
T = m₁g
So,
m₁g = m₂g (Sin 31.5° - 0.200 x cos 31.5°)
m₁ = 11.3 x (0.0840 - 0.2 x 0.996)
m₁ = 11.3 x (0.1152)
m₁ = 1.30176 kg
Hence, the mass of block 1 is 1.30176 kg.
Learn more about tension here:https://brainly.com/question/14294135
#SPJ1