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For the given equation, find the values of a, b, and c, determine the direction in which the parabola opens, and determine the y-intercept. Decide which table best illustrates these values for the equation: y = negative 4 x squared

Sagot :

The values of a, b, and c are -4,0 and 0 and the parabola opens downward with y-intercept (0,0).

we have

y=-4x^2

What is the standard form of the quadratic equation?

The quadratic equation in standard form is equal to

ax^2+bx+c=0

So,In this problem

a=-4, b=0 and c=0

The y-intercept is the value of y when the value of x is equal to zero

y=-4(0)^2=0

The y-intercept is the point (0,0)

The coefficient a is negative, therefore the parabola opens down.

To learn more about the quadratic equation visit:

https://brainly.com/question/1214333

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