From health tips to tech hacks, find it all on IDNLearn.com. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.
Sagot :
85-12 = 73 degrees needed
4.186 J/degree Celsius, so
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J
2.06 x 10^5 J are needed
4.186 J/degree Celsius, so
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J
2.06 x 10^5 J are needed
Answer:
206,265.15 Joules are needed to warm 675 grams of water from 12 degrees Celsius to 85 degrees Celsius.
Explanation:
Between heat and temperature there is a direct proportionality relationship, where the constant of proportionality depends on the substance that constitutes the body. So, the equation that allows you to calculate heat exchanges is:
Q = c * m * ΔT
Where Q is the heat exchanged for a body of mass m, constituted by a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- Q=?
- c=[tex]4.186 \frac{J}{g*degrees Celsius}[/tex]
- m=675 g
- ΔT=Tfinal-Tinitial=85 degrees Celsius - 12 degrees Celsius= 73 degrees Celsius.
Replacing:
[tex]Q=4.186 \frac{J}{g*degrees Celsius}*675 g*73 degrees Celsius[/tex]
Resolving you get:
Q=206,265.15 J
206,265.15 Joules are needed to warm 675 grams of water from 12 degrees Celsius to 85 degrees Celsius.
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Find clear answers at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.
