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The focal length of a diverging lens is negative. If f = −26 cm or a particular diverging lens, where will the image be formed of an object located 63 cm to the left of the lens on the optical axis?

.... cm to the left of the lens

....What is the magnification of the image?

Sagot :

Onyebuchinnajiidn

The distance of the image formed is 44.27 cm and the magnification of the image is 0.7.

Location of the image

The image distance formed by the lens is calculated as follows;

1/v + 1/u = -1/f

where;

  • v is the image distance
  • u is the object distance
  • f is the focal length of the lens

1/v = -1/f - 1/u

1/v = -(-1/26) - 1/63

1/v = 1/26 - 1/63

1/v = 0.022588

v = 1/0.022588

v = 44.27 cm

What is magnification of lens?

The magnification of a lens is defined as the ratio of the height of an image to the height of an object.

Magnification of the image formed

The magnification of the image is calculated as follows;

Magnification = image distance/object distance

M = 44.27/63

M = 0.7

Thus, the distance of the image formed is 44.27 cm and the magnification of the image is 0.7.

Learn more about magnification here: https://brainly.com/question/1599771

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