Answered

Get the information you need with the help of IDNLearn.com's expert community. Get comprehensive answers to all your questions from our network of experienced experts.

There is a set of 12 cards numbered 1 to 12. A card is chosen at random. Event A is choosing a number less
than 6. Event B is choosing a number divisible by 3. A diagram is given below.
(Can you help with #4 if you know it:)

There Is A Set Of 12 Cards Numbered 1 To 12 A Card Is Chosen At Random Event A Is Choosing A Number Less Than 6 Event B Is Choosing A Number Divisible By 3 A Di class=

Sagot :

The number of permutations of picking 4 pens from the box is 30.

There are six different unique colored pens in a box.

We have to select four pens from the different unique colored pens.

We have to find in how many different orders the four pens can be selected.

What is a permutation?

A permutation is the number of different arrangements of a set of items in a particular definite order.

The formula used for permutation of n items for r selection is:

    [tex]^nP_r = \frac{n!}{r!}[/tex]

Where n! = n(n-1)(n-2)(n-3)..........1 and r! = r(r-1)(r-2)(r-3)........1

We have,

Number of colored pens = 6

n = 6.

Number of pens to be selected = 4

r = 4

Applying the permutation formula.

We get,

= [tex]^6P_4[/tex]

= 6! / 4!

=(6x5x4x3x2x1 ) / ( 4x3x2x1)

= 6x5

=30

Thus the number of permutations of picking  4 pens from a total of 6 unique colored pens in the box is 30.

Learn more about permutation here:

https://brainly.com/question/14767366

#SPJ1

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.