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Please help quick
[tex]y=\frac{-1}{2\sqrt{x^{3} } }[/tex]

can you put step-by-step no verbal explanation needed how I can get to
[tex]y=\frac{-2}{x\sqrt{x} }[/tex]

Sagot :

The equation y=[tex]-1/2\sqrt{x^{3} }[/tex] does not give result to y=-2/[tex]x\sqrt{x}[/tex].

Given two equations y=[tex]-1/2\sqrt{x^{3} }[/tex] and y=-2/[tex]x\sqrt{x}[/tex].

We are required to find that how the first equation will result in second equation.

Equation is like a relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c. It may be a linear equation,cubic or quadratic equation or many more depending on the power if variable.

Taking the first equation.

y=[tex]-1/2\sqrt{x^{3} }[/tex]

Interchange the power of x.

y=-1/2[tex]\sqrt{x} ^{3}[/tex]

Now multiply [tex]\sqrt{x}[/tex] three times.

y=-1/2[tex]\sqrt{x} \sqrt{x} \sqrt{x}[/tex]

Now [tex]\sqrt{x} \sqrt{x}[/tex] will result in x.

y=-1/2x[tex]\sqrt{x}[/tex]

You can see our result is not matching the second equation.

Hence the equation y=[tex]-1/2\sqrt{x^{3} }[/tex] does not give result to y=-2/[tex]x\sqrt{x}[/tex].

Learn more about equations at https://brainly.com/question/2972832

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