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What is the equation of the line through (1, 6) and (0, 2)?

Y=4x - 2

Y= -4x - 2

Y= -4x + 2

Y= -4x + 2


Sagot :

Answer: Y = 4x + 2

(It would be either the third or fourth choice since they are the same, one of them must be mistaken)

Step-by-step explanation:

Given information

(x₁, y₁) = (1, 6)

(x₂, y₂) = (0, 2)

Find the slope through the formula

[tex]Slope~=~\frac{y_2~-~y_1}{x_2~-~x_1}[/tex]

[tex]\Large Slope~=~\frac{2~-~6}{0~-~1}[/tex]

[tex]\Large Slope~=~\frac{-4}{-1}[/tex]

[tex]\Large Slope~=~4[/tex]

Substitute values into the linear form

Equation: y = mx + b

Point (0, 2)

y = mx + b

(2) = (4) (0) + b

2 = 0 + b

b = 2 - 0

b = 2

Therefore, the equation is [tex]\Large\boxed{y=4x+2}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

y = 4x+2

Step-by-step explanation:

The first step is to find the slope

m = ( y2-y1)/(x2-x1)

m = ( 2-6)/(0-1)

    = -4/-1

   = 4

The slope intercept form of the equation is

y = mx+b  where m is the slope and b is the y intercept

y = 4x+b

The y intercept is where x is equal to 0

The y intercept is 2

y = 4x+2