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Line p has an equation of y= – 8x+6. Line q, which is perpendicular to line p, includes the point (2, – 2). What is the equation of line q?

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The equation of line q is determined as y =  ¹/₈x - ⁹/₄.

What is slope?

The slope of a line is the change in y axis to change in x axis.

Slope of line P

y = – 8x + 6

from general line equation, y = mx + c

where;

  • m is slope

m = - 8

Slope of line q

m₂ = -1/m

m₂ = -1/-8

m₂ = 1/8

Equation of line q

(y - y₁) / (x - x₁) = m₂

(y + 2)/(x - 2) = 1/8

y + 2 = ¹/₈(x - 2)

y + 2 = ¹/₈x -  ¹/₄

y = ¹/₈x - ⁹/₄

Thus, the equation of line q is determined as y =  ¹/₈x - ⁹/₄.

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