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8x+4y=7
6x-8y=41
using ELIMINATION METHOD ​


Sagot :

Answer:

([tex]\frac{5}{2}[/tex] , - [tex]\frac{13}{4}[/tex] )

Step-by-step explanation:

8x + 4y = 7 → (1)

6x - 8y = 41 → (2)

multiplying (1) by 2 and adding to (2) will eliminate y

16x + 8y = 14 → (3)

add (2) and (3) term by term to eliminate y

22x + 0 = 55

22x = 55 ( divide both sides by 22 )

x = [tex]\frac{55}{22}[/tex] = [tex]\frac{5}{2}[/tex]

substitute this value into either of the 2 equations and solve for y

substituting into (1)

8([tex]\frac{5}{2}[/tex] ) + 4y = 7

20 + 4y = 7 ( subtract 20 from both sides )

4y = - 13 ( divide both sides by 4 )

y = - [tex]\frac{13}{4}[/tex]

solution is ( [tex]\frac{5}{2}[/tex] , - [tex]\frac{13}{4}[/tex] )

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