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Answer:
e^-4t e^-5t
Explanation:
solving s²+9s+20 quadratically we have (s+4)(s+5)
x(s) can be written as x(s) =(1/s+4)(1/s+5)
if we take the laplace inversve
L-¹ (s)=L-1(1/s+4) L-1(1/s+5)
we have e^-4t e^-5t