IDNLearn.com provides a user-friendly platform for finding and sharing accurate answers. Discover reliable answers to your questions with our extensive database of expert knowledge.
Sagot :
The 2nd term exists 12 and 7th term exceeds the 4th by 15 exists AP : 7,12,17,....
How to estimate the arithmetic progression?
Given : The second term exists 12th and the 7th term exceeds the 4th term by 15
The formula of the nth term :
[tex]$a_{n}=a+(n-1) d[/tex]
Where d exists a common difference
n be the number of terms
a be the first term
Substitute the value of n = 2
[tex]$a_{2}=a+(2-1) d=a+d[/tex]
Let, the second term exists 12
So, a + d = 12 ..........(1)
Substitute the value of n = 7
[tex]$a_{7}=a+(7-1) d=a+6 d[/tex]
Substitute n = 4
[tex]$a_{4}=a+(4-1) d=a+3 d[/tex]
We are given that the 7th term exceeds the 4th term by 15
So, a+6d-a-3d = 15
3d = 15
d = 5
Substitute the value of d in (1)
So, a+5 = 12
a = 12-5
a = 7
AP : a,a+d,a+2d,.... = 5, 7+5, 7+2(5),....=7,12,17,....
Therefore, AP : 7,12,17,....
To learn more about arithmetic progression refer to:
https://brainly.com/question/24191546
#SPJ9
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.