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Sagot :
The answer is x < 1.
Bring the constant to the other side.
- 4x - 6 < 2
- 4x < 4
Divide by 4 on both sides.
- 4x ÷ 4 < 4 ÷ 4
- x < 1
[tex]\Large\texttt{Answer}[/tex]
[tex]\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\quad\space\space\qquad\qquad\qquad}}[/tex]
[tex]\Large\texttt{Process}[/tex]
[tex]\rm{4x-6 < -2}[/tex]
Do you remember that we need to get x by itself to find its value?
We should do this:
⇨ Add 6 to both sides
[tex]\rm{4x-6+6 < -2+6}[/tex]
On the left hand side (lhs), the 6s add up to zero; on the right hand side (rhs), the -2 and 6 result in 4. Hence
[tex]\rm{4x < 4}[/tex]
Now divide both sides by 4
[tex]\rm{\cfrac{4x}{4} < \cfrac{4}{4}}[/tex]
Simplifying fractions gives us
[tex]\rm{x < 1}[/tex]
* what this means is: numbers less than 1 will make the statement true
[tex]\Large\texttt{Verification}[/tex]
Substitute 1 into the original inequality [tex]\boxed{4x-6 < -2}[/tex]
[tex]\rm{4(1)-6 < -2}[/tex]
[tex]\rm{4-6 < -2}[/tex]
Do the arithmetic
[tex]\rm{-2 < -2}[/tex]
Hope that helped
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