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How many moles of iron atoms are obtained from 320kg of iron oxide

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Eunice1234idn

Answer: 4010 mol of iron atoms

Explanation:

Given Information

Iron Oxide = Fe₂O₃

Mass = 320 kg

Given atomic mass / molecular weight

Fe = 55.8 g / mol

O = 16.0 g / mol

Fe₂O₃ = 55.8 × 2 + 16.0 × 3 = 159.6 g / mol

Given formula

n = m / M

  • n = number of moles
  • m = mass
  • M = molecular weight

Convert the unit of mass to Gram

1 kg = 1000 g

320 kg = 320 × 1000 = 320 000 g

Substitute values into the given formula

n = m / M

n = (320000) / (159.6)

n ≈ 2005 mol of Fe₂O₃

Calculate the number of moles of Fe (Iron atoms)

Since each mole of Fe₂O₃ has 2 moles of Fe, then:

                                 

                                 2005 × 2 =[tex]\Large\boxed{4010~mol~of~Fe}[/tex]

Hope this helps!! :)

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