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Write the equation of the line shown

Write The Equation Of The Line Shown class=

Sagot :

Answer:

y = [tex]\frac{1}{2}[/tex] x + 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 1) ← 2 points on the line

m = [tex]\frac{1-0}{0-(-2)}[/tex] = [tex]\frac{1}{0+2}[/tex] = [tex]\frac{1}{2}[/tex]

the line crosses the y- axis at (0, 1 ) ⇒ c = 1

y = [tex]\frac{1}{2}[/tex] x + 1 ← equation of line

The straight line equation is :

[tex]\boxed {y = mx + c}[/tex]

Here, c = 1 as it intersects (0, 1) on the y-axis.

The slope is :

  • m = 1 ÷ 2
  • m = 0.5

Hence, the equation will be :

y = 0.5x + 1

I hope it helped you solve the problem.

Good luck in your studies!

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