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Sagot :
When 3. 41 g of C6H12O6 is dissolved in 85 ml of water the molality is 2.2m.
What is molality?
Molality is the amount of a substance dissolved in a certain mass of solvent.
Molality = moles of solute/ mass of solvent (kg)
Given,
Mass of solute = 3.14g
Molar mass of solute = 180 g
Mole of solute= given mass/molar mass
= 3.14/180
= 0.0189 mol.
Volume of solvent = 85 ml
Density of water = 1 g/cm3
Density = mass/ volume
mass = density × volume
= 1× 85
= 85g
Molality = (0.0189/ 85) × 1000
= 2.2m
Thus we find that the molality of given solution is 2.2m.
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