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Sagot :
When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.
Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.
In other words osmolarity is the multiple if molarity
Osmolarity = i× molarity
Here i represents the van't Hoff factor,
[tex]Na_{3}PO_{4}[/tex] ⇒ [tex]3Na^{+} + PO_{4} ^{-}[/tex]
3 Moles of [tex]Na_{} ^{+}[/tex] + 1 mole [tex]PO_{4} ^{-}[/tex] = 4
The number of moles of particles of solute produced in solution are actually called osmoles.
As a result, the van't Hoff factor will be equal to
i=4 Moles ions produced (osmoles) 1mole [tex]Na_{3} PO_{4}[/tex] .dissolved =4
Since we know that,
[tex]Na_{3} PO_{4}[/tex] = [tex]2.0 * 10^{-3} M[/tex]
Osmolarity =
[tex]4*2.0*10^{-3} M[/tex] = [tex]8.0 * 10^{-3} osmol L -10s[/tex]
Thus, the Osmolarity of given solution is 0.008 osmol/L.
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