Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Get prompt and accurate answers to your questions from our community of knowledgeable experts.
Sagot :
The binding energy of the electron is 1.237 ×10^(-16) kj/ mol.
The given parameter
wavelength of photon,
λ = 0.999nm
= 0.999x10⁻⁹ m
K.E of emitted photon,
K.E = 940 ev
The binding energy of electron is calculated as follows:
From Einstein's mass defect equation=
ΔE = Δmc²
Also, from Einstein's photo electric equation=
E = Ф + K.E
Where;
Ф is binding energy of electron on metal surface.
The energy of on mole of electron, the emitted is calculated as:
[tex]E = hf =h \frac{c}{λ} = (6.626×10^{-34} ) × \frac{{3×10^{8} }}{0.999×10^{-9} } \\\\E= 1.989×10^{-16}[/tex]
The K.E of emitted electron in Joules is
[tex]K.E = 940 × \frac{1}{2} ×1.602 ×\ 10^{-19} J\\\\ = 0.752 × 10^{-16} J[/tex]
The binding energy is electron is calculated as:
[tex]Ф = E - K.E\\= (1.989 - 0.752) ×10^{-16}\\ =1.237 × 10^{-16} J[/tex]
Question: An X-ray photon of wavelength 0.999nm strikes a surface. The emitted electron has a kinetic energy of 940 eV. What isthe binding energy of the electron in kJ/mol? (KE=1/2mv2; 1 electron volt (eV) = 1.602 x10-19J)
Learn more about binding energy: https://brainly.com/question/15718710
#SPJ4
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.
