Answered

IDNLearn.com: Your go-to resource for finding expert answers. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.

In a region where the electric field is uniform and points in the x direction, the electric potential is -2000 v at x = 8 m and is 400 v at x = 2 m. what is the magnitude of the electric field?

Sagot :

Tanisharawat014idn

The magnitude of the uniform electric field, if the electric potential is -2000 v at x = 8m and is 400 v at x = 2 m in x direction will be, 400V/m.

To find the answer, we have to know more about the electric field.

How to find the magnitude of uniform electric field?

  • a space where other charged particles or things would be forced to move away from a charged particle or item is called the electric field.
  • The expression for electric field in terms of potential V and the distance x can be written as,

                                         [tex]E=\frac{dV}{dx}[/tex]

where, dV is the potential difference at two different points of the conductor and dx is the difference of the points.

  • Thus, the magnitude of electric field can be written as,

                      [tex]|E|=|-(\frac{dV}{dx} )|=|-(\frac{-2000-400}{8-2} )|\\\\|E|=400V/m[/tex]

Thus, we can conclude that, the magnitude of the uniform electric field, if the electric potential is -2000 v at x = 8m and is 400 v at x = 2 m in x direction will be, 400V/m.

Learn more about the electric field here:

https://brainly.com/question/27752270

#SPJ4

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.