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91.4 grams mass of KCl is required.
Concentration = moles/Volume
2.45M=mol/0.5L
2.45M⋅0.5L=mol
mol=1.225
Convert no. of moles to grams using the atomic mass of K + Cl
1.225mol⋅(39.1+35.5)/gmol
1.225mol⋅74.6g
mol=1.225⋅74.6g = 91.4g
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