Answered

Explore a diverse range of topics and get answers from knowledgeable individuals on IDNLearn.com. Our platform offers reliable and detailed answers, ensuring you have the information you need.

A 600-kg car makes a 90° turn. its speed before the turn is 21. 0 m/s and after the turn it is 24. 0 m/s. what is the magnitude of the change in the car's momentum during the turn?

Sagot :

The magnitude of the change in the car's momentum during the turn is

[tex] = 1.9 \times 10 {}^{3} kgm/s[/tex]

What is momentum?

Momentum can be defined as "mass in motion." All objects have mass,so if an object is moving, then it has momentum - it has its mass in motion.

Given:

V1=21m/s

V2=24m/s

m=600kg

To Find:

momentum

Now using Pythagoras theorem

[tex]f = ((600)(21)) {}^{2} + ((600)(24)) {}^{2} [/tex]

[tex]f = \sqrt{1.59 \times 10 {}^{8} + 2.07 \times 10 {}^{8} } [/tex]

[tex] = 1.9 \times 10 {}^{3} kgm/s[/tex]

learn more about momentum from here: https://brainly.com/question/28165726

#SPJ4

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.