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Sagot :
The pressure drop in pascal is 3.824*10^4 Pascals.
To find the answer, we need to know about the Poiseuille's formula.
How to find the pressure drop in pascal?
- We have the Poiseuille's formula,
[tex]Q=\frac{\pi r^4P}{8\beta l}[/tex]
- where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
- By substituting values and rearranging we will get the pressure drop as,
[tex]P=3.284Pascals[/tex]
Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.
Learn more about the Poiseuille's formula here:
brainly.com/question/13180459
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