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The set of reaction conditions would favor a sn2 reaction on 2-bromo-3-methylbutane is a strong nucleophile in an aprotic solvent. The correct option is D.
It is a type of nucleophilic substitution reaction. This mechanism is common in organic chemistry. In these reactions, one bond is break and one bond is formed simultaneously.
The sn2 is a nucleophile reaction, and it is a strong nucleophile. This type of reaction, will occur in the compounds in which there is one alkyl halide group and a good leaving group.
In 2-bromo-3-methylbutane, there is a bromine and methyl group both, so the favor would be a strong nucleophile in an aprotic solvent.
Thus, the correct option is D) strong nucleophile in an aprotic solvent.
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The question is incomplete. Your complete question is given below:
A) weak nucleophile in a protic solvent
B) weak nucleophile in an aprotic solvent
C) strong nucleophile in a protic solvent
D) strong nucleophile in an aprotic solvent
E) none of the above