Connect with experts and get insightful answers on IDNLearn.com. Discover reliable and timely information on any topic from our network of knowledgeable professionals.
Sagot :
In a particular electrolysis process, Eο cathode = -1.151 v and Eο anode = 1.548 V. The minimum voltage must be applied to drive the non-spontaneous process is 2.699V.
Electrode Potential Or Voltage is the emf of a galvanic cell where emf is called as the Electromotive force.
Electrode Potential of a spontaneous cell is positive. Hence to make a non-spontaneous cell into a spontaneous cell, the voltage or potential applied should be positive to make the cell working.
We know that,
Electrode Potential = Electrode Potential of cathode - Electrode Potential of anode
where, Electrode Potential of cathode = -1.151V
Electrode Potential of anode = 1.548V
On substituting,
⇒ Electrode Potential = -1.151V - 1.548V
⇒ Electrode Potential = - 2.699V
Hence, the minimum voltage to drive a non-spontaneous cell into a spontaneous cell should be at least 2.699V.
Learn more about Electrode Potential here, https://brainly.com/question/17060277
#SPJ4
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.
