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A mass weighing 16 pounds is attached to a spring whose spring constant is 25 lb/ft. what is the period of simple harmonic motion?

Sagot :

The time period of the spring - mass system undergoing simple harmonic motion is 5.024 seconds.

We have a mass weighing 16 pounds which is attached to a spring whose spring constant is 25 lb/ft . This complete spring - mass system is undergoing simple harmonic motion.

We have to calculate the time period of this simple harmonic motion.

What is the formula to calculate the Time period of a spring - mass system performing Simple harmonic motion?

The formula to calculate the time period of a spring - mass system undergoing simple harmonic motion is -

[tex]T=2\pi \sqrt{\frac{m}{k} }[/tex]

Where -

T is the time period of spring - mass simple harmonic motion.

m is the mass of body

k is the spring constant

In the question given -

mass (m) = 16 pounds

Spring constant (k) = 25 lb/ft

Substituting the values in the formula above -

T =  [tex]2\pi \sqrt{\frac{16}{25} }[/tex]  = [tex]\frac{2\pi \times4}{5}[/tex]  = 5.024 seconds

Hence, the time period of the spring - mass system undergoing simple harmonic motion is 5.024 seconds.

To solve more questions on spring - mass system, visit the link below -

brainly.com/question/13107443

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