From everyday questions to specialized queries, IDNLearn.com has the answers. Get comprehensive and trustworthy answers to all your questions from our knowledgeable community members.

Of all closed rectangular boxes of volume 64 ft3, what is the smallest surface area?

Sagot :

The smallest surface area of cubic rectangular boxes = 96 ft²

What is surface area?

An object with three dimensions is solid and has both height and depth. A sphere and a cube, for instance, have three dimensions, whereas a circle and a square do not.

A three-dimensional shape's total surface area equals the sum of its side's surface areas. The measured area of all surfaces of three-dimensional solids, such as cubes, spheres, prisms, and pyramids, is expressed in square units.

Since it is a closed rectangular box so, there will be two equal sides.

According to the given Information:

Volume = 64 ft³

Volume of rectangular cube = hx²

Surface area of rectangular cube = 2x²+4hx

Equating the above equation we get, hx² = 64

                                                               h=64/x²

Put the value of h in surface area formula,

S = 2x² + 4(64/x²)*x

S = 2x² + 256/x

For the surface area to be minimum,

ds/dx = 0

4x - (256/x²) = 0

4x³ = 256

x³ = 64

x = 4 ft

Therefore, the smallest surface area

= 2(4)² + (256/4)

S = 32 + 64

= 96 ft²

To know more about the surface area visit:

https://brainly.com/question/10604587

#SPJ4