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Use part 1 of the fundamental theorem of calculus to find the derivative of the function. g(x) = x e5t2 − 4t dt 4 g'(x) =

Sagot :

The derivative of the given equation is [tex]\frac{dg(x) }{dx} = {e^{5x^{2} - 4x} } \,[/tex].

According to the statement

we have given that the statement and we have to find the derivative of that term.

So, We know that the

The given equation is

[tex]g(t) = \int\limits^x_4 {e^{5t^{2} - 4t} } \, dt[/tex]

Now find the derivative of that term

We find the derivative of the given term is with the help of the FTC.

And then

[tex]\frac{dg(x) }{dt} = {e^{5x^{2} - 4x} } \, \frac{dx}{dx}[/tex]

Then the equation become is

[tex]\frac{dg(x) }{dx} = {e^{5x^{2} - 4x} } \,[/tex]

So, this is the derivative of the given equation.

So, The derivative of the given equation is [tex]\frac{dg(x) }{dx} = {e^{5x^{2} - 4x} } \,[/tex].

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