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The total length of school installs fencing around a hexagon-shaped area for an outside concert, is 36 yards.
To find the fencing used by the school:
The distance formula can be given as: [tex]d=\sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1})^{2} }[/tex]
First, we must calculate the length of the hexagon using the distance formula.
The hexagon's coordinates, according to the graph, are:
(-5, 4), (0, 6), (5, 4), (6, -2), (0, -4), and (-6, -2)
The distance between (-5, 4), (0, 6): [tex]d=\sqrt{(5)^{2} +(6-4)^{2} }[/tex]
Similarly, the distance between (-5, 4) and (6, -2):
And the distance between (6, -2) and (0, -4):
Amount of fencing required = 2(√29+√37+√40):
Therefore, the total length of school installs fencing around a hexagon-shaped area for an outside concert, is 36 yards.
Know more about the distance formula here:
https://brainly.com/question/20761638
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The complete question is given below:
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
The school puts up fencing around an area in the shape of a hexagon for an outdoor concert. How much fencing does the school use? Round your answer to the nearest whole yard.
