Get the best answers to your questions with the help of IDNLearn.com's experts. Our experts are ready to provide prompt and detailed answers to any questions you may have.
Sagot :
A 1. 7 m solution of the acid ha has a ph of 1. 0, then the ka of the acid is 6.25×10^(-3).
What is acid dissociation constant?
The acid dissociation constant is defined as the value which is used to measure the strength of the specific acid in the solution.
Equation for general dissociation of strong or weak acid is
HA ----- (H+) + ( A-)
Ka can be expressed as
Ka = [H+] [A-]/[HA]
where [H+] is the concentration of H+ ions
Now, we will find the value of concentration of H+ ions
pH = -log [H+]
1 = -log[H+]
[H+] = antilog(-1)
[H+] = 0.1
By using ICE table, we find that the concentration of [HA] is
1.7-0.1
= 1.6
By substituting all the values we get,
Ka = 0.1 × 0.1/1.6
= 6.25×10^(-3)
Thus, we find that the Ka value of the given solution is 6.25×10^(-3).
learn more about acid dissociation constant:
https://brainly.com/question/2728613
#SPJ4
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.