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A positive charge of 94. 0 NC is 22. 0 cm from a negative charge of 53. 0 NC. The force on one of the charges due to the other is approximately 92.6× 10⁹ N
Force between the two charges depends upon the charges, distance between the charges and the medium between the two charges. It is given by:
F = kq₁q₂ / r²
where q₁ is the charge of the first charge
q₂ is the charge of the second charge
r is the distance between the charges
k is the permitivitty of medium
F is the force between the two charges
Given , q₁ = 94NC
q₂ = 53NC
r = 22cm = 0.22m
On subsituting,
F = 9 × 10⁹ × 94 × 53 / (0.22)²
⇒ F = 92.6 × 10⁹ N
Since, the force between the two charges is equal on both the charges hence, force on one of the charges due to the other is approximately 92.6× 10⁹ N.
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