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Sagot :
If the probability of obtaining success is 0.3 and the value of n is 9 then the probability at the value of x be 3 is 0.3811.
Given that the value of n is 9 and the value of p is 0.3.
We are required to find the probability when the value of x is equal to 3.
Probability is the calculation of chance of happening an event among all the events possible.It lies between 0 and 1.
Probability=Number of items/total items.
Binomial probability is basically the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes.
[tex](a+b)^{n}[/tex]=[tex]nC_{0}a^{0} b^{n-0} +nC_{1}a^{1} b^{n-1} +................nC_{n}a^{n} b^{0}[/tex]
We have to find the value when n=9, p is 0.3 and r=3.
=[tex]9C_{3} (0.3)^{3} (1-0.3)^{6}[/tex]
=9!/3!6!*0.027*0.16807
=84*0.00453789
=0.381182
Hence if the probability of obtaining success is 0.3 and the value of n is 9 then the probability at the value of x be 3 is 0.3811.
Learn more about probability at https://brainly.com/question/24756209
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