Answered

IDNLearn.com provides a collaborative platform for sharing and gaining knowledge. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.

Sloane kicked a soccer ball off the ground at a speed of 48 feet per second. The height of the ball can be represented by the function H(t) = −16t2 + 48t, where t is the time in seconds. How many seconds did the ball travel before returning the ground?

Sagot :

If the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

Given that the speed of the ball after kicking is 48 feet per second and the function that represents the height of the ball is [tex]-16t^{2} +48t[/tex].

We are required to find the time that the ball took to travel before returning the ground.

We know that speed is the distance a thing covers in a particular time period.

The height of the ball after t seconds is as follows:

h(t)=[tex]-16t^{2} +48t[/tex]

It is at ground at the instants of t.

Hence,

[tex]-16t^{2} +48t[/tex]=0

-16t(t-3)=0

We want value of t different of 0, hence :

t-3=0

t=3.

Hence if the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

Learn more about speed at https://brainly.com/question/4931057

#SPJ1

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.