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Sagot :
With the help of the motion equation, it is calculated that if the vehicle slows down at a pace of -4.0 m/s², stopping will take 7.5 seconds.
Motion equation:
Three motion equations commonly referred to as the rules of constant acceleration, exist for a uniform acceleration. In order to derive the components such as displacement(s), velocity(initial =u and final = v), time(t), and acceleration(a), these equations are utilized. They are therefore only applicable in straight-line motion with constant acceleration. Here are the three equations:
- v=u+at or, v = u-at
- v²=u²+2as
- s= ut+1/2 at²
Calculating the time :
The formula for the motion equation is
v = u - at
v = final velocity
u = initial velocity
a = acceleration
t = time
Here, v = 0 ,as the automobile comes to a stop
u = 30 m/s
a = -4 m/s²
So, v = u - at
⇒0 = 30 - 4t
⇒4t = 30
⇒t = 30/4
⇒t = 7.5 seconds
Therefore, the required time calculated is 7.5 seconds.
Learn more about motion equations here:
https://brainly.com/question/13514745
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