The minimum value of data is 24,lower quartile is 29,median is 41, upper quartile is 50 and maximum value is 56 and the interquartile range is 21.
Given a data about ages of 13 history teacher as under:
24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56.
We are required to find the minimum value, lower quartile,median,upper quartile,maximum value, interquartile range.
The minmum value is 24.
Lower quartile=(n+1)/4 th term
=(13+1)/4
=7/2
=3.5
Lower quartile=(29+29)/2
=29
Median=(n/2)th term
=13/2 th term
=6.5 th term
Median=(39+43)/2
=82/2
=41
Upper quartile=3(n+1)/4 th term
=3(13+1)/4
=3*14/4
=10.5 th term
Upper quartile=(49+51)/2=100/2=50
Inter quartile range=Upper quartile- lower quartile
=50-29
=21
Hence the minimum value of data is 24,lower quartile is 29,median is 41, upper quartile is 50 and maximum value is 56 and the interquartile range is 21.
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