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Sagot :
The molar mass of the other gas is 450.56 g.
Calculation:
Relation between rate of diffusion and molar mass of two gases is given by:
r₁/r₂ = (√m₂)/(√m₁)
Given,
r₁ = 3.2r₂
(r₁ is the diffusion rate of CO₂ and r₂ is the diffusion rate of the other gas)
We know
m₁ = molar mass of CO₂ = 44 g
To find,
m₂ = molar mass of the other gas =?
Put the values in the above equation,
r₁/r₂ = (√m₂)/(√m₁)
3.2r₂/r₂ = (√m₂)/(√44)
3.2 = (√m₂)/(√44)
Squaring both the sides,
10.24 = m₂/44
m₂ = 10.24 (44)
m₂ = 450.56 g
Hence, the molar mass of the other gas is 450.56 g.
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