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Sagot :
A particle moving at speed 0.24 c has momentum P₀. The speed of the particle is increased to 0.68 c then its momentum would be 2.85P₀.
Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction.
Mathematically the formula of the momentum is
P = mv
where P is the momentum of the particle
m is the mass of the particle
v is the velocity by which the particle is moving
As mentioned in the question when the particle is moving with 0.24c velocity it has a momentum of P₀
P₀ = m*(0.24c)
If the speed of the particle is increased to 0.68 c the momentum would be
P=m*(0.68c)
by dividing the second equation from the first one
P₀/P = 0.24c/0.68c
P₀/P = 0.35
P =2.85P₀
To know more about Momentum refer:
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