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The minimum value of f(8) - f(3) is 20.
The maximum value of f(8) - f(3) is 25.
In the question, we are given that, 4 ≤ f'(x) ≤ 5 for all values of x.
Taking the given inequality as (i).
We are asked to find the minimum and maximum possible values of f(8) - f(3).
We multiply (i) by dx throughout, to get:
4dx ≤ f'(x)dx ≤ 5dx.
To find this, we integrate (i) in the definite interval [8, 3] with respect to dx, to get:
[tex]\int_{3}^{8}4dx \leq \int_{3}^{8}f'(x)dx \leq \int_{3}^{8}5dx\\\Rightarrow [4x]_{3}^{8} \leq [f(x)]_{3}^{8} \leq [5x]_{3}^{8}\\\Rightarrow 4*8 - 4*3 \leq f(8)-f(3) \leq 5*8 - 5*3\\\Rightarrow 20 \leq f(8) -f(3) \leq 25[/tex]
Thus, the minimum value of f(8) - f(3) is 20.
The maximum value of f(8) - f(3) is 25.
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