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Sagot :
A student makes up a 0. 6 M solution of acetic acid then its pOH of this solution is 13.77
Calculation ,
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
We have to find pH of the acetic acid .
[ [tex]H^{+}[/tex] ] = 0. 6
pH = -㏒[ [tex]H^{+}[/tex] ]
pH = -㏒ [ 0. 6 ]
pH = 0.22
pH + pOH = 14
pOH = 14 - pOH = 14 - 0.22 = 13.77
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