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The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notice that the ages are ordered from least to greatest. Give the five-number summary and the interquartile range for the data set. Five-number summary
Minimum:
Lower quartile:
Median:
Upper quartile:
Maximum: Interquartile range:

Sagot :

The Five number summary for the given data:

Minimum: 24

Lower quartile: Q1 = 29

Median: 43

Upper quartile: Q3 = 50

Maximum: 56

Interquartile range: IQR = 21

What is the interquartile range?

The interquartile range is calculated by

IQR = Q3 - Q1

Where Q3 - upper quartile and Q1 - lower quartile

Q3 = 3/4(n + 1) th term

Q1 = 1/4(n + 1) th term

Calculation:

The given data points are

24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56

where n = 13

Maximum data value = 56

Minimum data value = 24

Calculating Median:

Median = (n+1)/2 th term

⇒ Median = (13 + 1)/2 = 7th term

∴ Median = 43

Calculating the quartiles:

Upper quartile Q3 = 3/4(n + 1)th term

⇒ Q3 = 3/4(13 + 1) = 10.5

⇒ Q3 = 10th term + 1/2(11th term - 10th term)

⇒ Q3 = 49 + 1/2(51 - 49)

⇒ Q3 = 49 + 1

∴ Q = 50

Lower quartile Q1 = 1/4(n + 1)th term

⇒ Q1 = 1/4(13 + 1) = 3.5

⇒ Q1 = 3rd term + 1/2(4th term - 3rd term)

⇒ Q1 = 29 + 1/2(29 - 29)

∴ Q1 = 29

Calculating the IQR:

IQR = Q3 - Q1

      = 50 - 29

      = 21

Thus, the interquartile range is 21.

Therefore, the five-number summary for the given data:

Minimum: 24

Lower quartile: Q1 = 29

Median: 43

Upper quartile: Q3 = 50

Maximum: 56

Interquartile range: IQR = 21

Learn more about the five-number summary here:

https://brainly.com/question/17110151

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