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Sagot :
The distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone. This can be obtained by converting the conditions to equations.
Find the equation for the relationship between the distance and number of seconds:
A linear function containing one dependent and one independent variable.
It can be represented using the equation,
y = mx + c
where m is the slope
It is given in the question that,
Rachel is a stunt driver and one time during a gig where she escaped from a building about to explode she drove to get to the safe zone at 24 meters per second.
After 4 seconds of driving, she was 70 meters away from the safe zone.
Let, D(t) be the distance to the safe zone (measured in meters) and t be the time (measured in seconds)
After 4 seconds of driving, she was 70 meters away from the safe zone.
⇒ This means that at t = 4 seconds, D(4) = 70 meters
Rachel's rate is the slope of the function D(t). Since the distance is decreasing when the time is increasing, the slope must be negative
⇒ m = - 24
y = mx + c
⇒ D(t) = (-24)t + c
Put t = 4,
D(4) = (-24)4 + c
70 = -96 + c ⇒ c = 166
⇒ D(t) = 166 - 24t
Hence the distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone.
Learn more about linear function here:
brainly.com/question/13919345
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