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How many grams of nitrogen gas are formed when 18. 1 g of ammonia is reacted with 90. 4 g of copper(ii) oxide?

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10.55 grams of nitrogen gas are formed when 18. 1 g of ammonia is reacted with 90. 4 g of copper(ii) oxide.

What is stoichiometric law?

The laws which deals with the composition of substance by mass or his volume are called the laws of stoichiometry.

The laws of stoichiometry are:

  •   Law of conservation of mass
  •   Law of definite/constant proportion
  •   Law of multiple proportion
  •   Law of reciprocal proportions
  •   Law of gaseous volume

Reaction:

3CuO + 2NH₃ → N₂ + 3 Cu + 3 H₂O

n(CuO) = m(CuO) / 64 + 16 = 90.4 / 80 = 1.13 mol   (molar mass of CuO = 90.4)

n(NH₃) = m(NH₃) / 14+3 = 18.1 / 17= 1.065mol   (molar mass of NH₃ = 18)

For 1.065 mol of NH3 undergoing the reaction, 3/2  times larger amount of CuO is needed.

CuO is 1.6 mol but it's only 1.13 of it so CuO is a limiting reactant, we must count stoichiometry by amount of this reactant.

n(CuO) = 1.13 mol,

n(N₂) = n(CuO) / 3 = 1.13 / 3 = 0.376 mol

m(N₂) = 0.376 x 28 = 10.55 grams

10.55 grams of nitrogen gas are formed when 18. 1 g of ammonia is reacted with 90. 4 g of copper(ii) oxide.

Learn more about stoichiometric law, Here:

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