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The expression which correctly sets up the quadratic formula to solve the equation is (A) [tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex].
What is an expression?
To find which expression correctly sets up the quadratic formula to solve the equation:
Theory of quadratic equation - A quadratic equation is defined as any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power.
An example of a quadratic equation in x is [tex]-4x^{2} +4=9x[/tex].
How to solve any quadratic equation using the Sridharacharya formula?
Let us represent a general quadratic equation in x, [tex]ax^{2} +bx+c=0[/tex] where a, b and c are coefficients of the terms.
According to the Sridharacharya formula, the value of x or the roots of the quadratic equation is -
[tex]x=\frac{-b+-\sqrt{(b)^{2}-4(a)(c) } }{2a}[/tex]
The given equation is [tex]x^{2} -4x+3=0[/tex]
Comparing with the general equation of quadratic equation, we get a = 1, b = -4 , c = 3.
Putting the values of coefficients in the Sridharacharya formula,
[tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex] which is (A).
Therefore, the expression which correctly sets up the quadratic formula to solve the equation is (A) [tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex].
Know more about expressions here:
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The complete question is shown below:
Consider this quadratic equation. x^2+3=4x. Which expression correctly sets up the quadratic formula to solve the equation?
