Answered

IDNLearn.com is the perfect place to get detailed and accurate answers to your questions. Join our knowledgeable community and access a wealth of reliable answers to your most pressing questions.

A 15. 0 ampere current flows through a 4. 75 m section of wire, perpendicular to a 0. 250 t magnetic field. what is the magnitude of the force exerted by the field on the wire section?

Sagot :

Jacob193idn

Answer:

Approximately [tex]17.8\; {\rm L}[/tex].

Explanation:

Consider a straight wire section of length [tex]L[/tex] carrying a current of [tex]I[/tex]. If that wire is placed in a magnetic field of strength [tex]B[/tex] at an angle of [tex]\theta[/tex] relative to the field, the magnitude of the magnetic force on this wire would be:

[tex]F = B\, I\, L\, \sin(\theta)[/tex].

In this question, [tex]\theta = 90^{\circ}[/tex] since the wire is perpendicular to the magnetic field. The magnitude of the magnetic force on this wire would be:

[tex]\begin{aligned}F &= B\, I\, L\, \sin(\theta) \\ &= (0.250\; {\rm T}) \, (15.0\; {\rm A}) \, (4.75\; {\rm m})\, (\sin(90^{\circ}) \\ &\approx 17.8\; {\rm N} \end{aligned}[/tex].

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.